Numerical

A quartz crystal of thickness 1.5 mm vibrating with resonance. Calculate it’s fundamental frequency if the Young’s modulus of quartz crystal is 7.9×10^{10}N/m^{2} and density is 2650 kg/m^{3} .

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#### Solution

Given Data :- `t_1 = 1mm = 10^-3 mm Y = 7.9 × 10^10N/m^2`

ρ = 2650 kg/m^{3}

Formula :- f =`1/(2t) √Y/ ρ`

Calculations :- `f = 1/(2 × 10^-3) √(7.9 ×10^10)/2650

= 2.73 MHz`

Answers :- Frequency = 2.73 MHz

Concept: Study of characteristics of unit cell of Diamond, ZnS, NaCl and HCP;

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