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A quartz crystal of thickness 1.5 mm vibrating with resonance. Calculate it’s fundamental frequency if the Young’s modulus of quartz crystal is 7.9×1010N/m2 and density is 2650 kg/m3 . - Applied Physics 1

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Numerical

A quartz crystal of thickness 1.5 mm vibrating with resonance. Calculate it’s fundamental frequency if the Young’s modulus of quartz crystal is 7.9×1010N/m2 and density is 2650 kg/m3

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Solution

Given Data :- `t_1 = 1mm = 10^-3 mm  Y = 7.9 × 10^10N/m^2`
ρ = 2650 kg/m3

Formula :- f =` 1/(2t)  √Y/ ρ`

Calculations :- `f = 1/(2 × 10^-3) √(7.9 ×10^10)/2650
= 2.73 MHz`

Answers :- Frequency = 2.73 MHz

Concept: Study of characteristics of unit cell of Diamond, ZnS, NaCl and HCP;
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