A Quartz Crystal of Thickness 1 Mm is Vibrating at Resonance. Calculate Its Fundamental Frequency. (Assume that for Quartz, Y= 7.9x 1010 N/M2 and P = 2.650 Gm/Cc. - Applied Physics 1
A quartz crystal of thickness 1 mm is vibrating at resonance. Calculate its fundamental frequency. (Assume that for quartz, Y= 7.9x 1010 N/m2 and p = 2.650 gm/cc.
Data: t1 = 1 mm= 103 m, Y = 7.8 x 1010 N/m2,
p = 2. 650 gm/cc = 2650 kg/m3
Formula: f = 1/2t ·√Y/p
Calculations: f = 1/2x 103 √7.9 × 1010/2650 = 2.73 MHz
Answer : Frequency = 2. 73 MHz
Concept: Study of characteristics of unit cell of Diamond, ZnS, NaCl and HCP;
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