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A proton and an electron have the same kinetic energy. Which one has a greater de Broglie wavelength? Justify.

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#### Solution

de-Broglie wavelength of the particle is λ = `"h"/"p" = "h"/sqrt(2"mK")`

i.e. `λ ∝ "h"/sqrt"m"`

As for m_{e} < m_{p},

So λ_{e} > λ_{p}

Hence wavelength of electron is greater than that of proton.

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