MCQ

A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in time t_{1} if the elevator is stationary and in time t_{2} if it is moving uniformly. Then

#### Options

t

_{1}= t_{2}t

_{1}< t_{2}t

_{1}> t_{2}t

_{1}< t_{2}or t_{1}> t_{2}depending on whether the lift is going up or down.

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#### Solution

t_{1} = t_{2}

After the coin is dropped, the only force acting on it is gravity, which is same for both the cases.

So t_{1} = t_{2}.

Concept: Newton's Third Law of Motion

Is there an error in this question or solution?

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