A Person Bought Two Bicycles for ₹1600 and Sold the First at 10% Profit and the Second at 20% Profit. If He Sold the First at 20% Profit and the Second at 10% Profit, He Would Get ₹5 More. the D - Mathematics

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MCQ

A person bought two bicycles for ₹1600 and sold the first at 10% profit and the second at 20% profit. If he sold the first at 20% profit and the second at 10% profit, he would get ₹5 more. The difference in the cost price of the two bicycles was

Options

  • ₹25

  • ₹75

  • ₹50

  • ₹40

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Solution

₹50
Explanation :

Let the cost price of the first bicycle be ₹ x.
Then, the cost price of second bicycle = ₹(1600 - x)
According to the given condition,
20% of x + 10% of (1600 - x) -  [10% of x + 20% of (1600 - x)] = 5

`⇒ [(20xxx)/100+(10xx(1600-x))/100] -[(10xxx)/100+(20xx(1600-x))/100]=5` 

⇒`(x/5+(1600-x)/10)- (x/10+(1600-x)/5)=5`

⇒`x/5-x/10+((1600-x))/10-((1600-x))/5=5` 

⇒`(2x-x)/10+((1600-x)-2(1600-x))/10=5`

⇒`(x+1600-x-3200+2x)/10=5`

⇒`(-1600+2x)/10=5 `

⇒`2x=1600+50`

⇒`x=1650/2=825`

∴ Cost of second bicycle = (1600 - 825) = ₹775
Required difference = 825 - 775
= ₹50

Concept: Profit and Loss (Entrance Exam)
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