# A Pendulum Clock that Keeps Correct Time on the Earth is Taken to the Moon. It Will Run - Physics

MCQ

A pendulum clock that keeps correct time on the earth is taken to the moon. It will run

#### Options

• at correct rate

• 6 times faster

• $\sqrt{6}$ times faster

• $\sqrt{6}$ times slower

#### Solution

(d)$\sqrt{6}$ times slower

The acceleration due to gravity at moon is g/6.
Time period of pendulum is given by,

$T = 2\pi\sqrt{\frac{l}{g}}$

Therefore, on moon, time period will be :

Tmoon = $2\pi\sqrt{\frac{l}{g_{moon}}} = 2\pi\sqrt{\frac{l}{( \frac{g}{6})}} = \sqrt{6}(2\pi\sqrt{\frac{l}{g}}) = \sqrt{6}T$

Is there an error in this question or solution?

#### APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 12 Simple Harmonics Motion
MCQ | Q 18 | Page 251