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A Pendulum Clock that Keeps Correct Time on the Earth is Taken to the Moon. It Will Run - Physics

MCQ

A pendulum clock that keeps correct time on the earth is taken to the moon. It will run

Options

  • at correct rate

  • 6 times faster

  • \[\sqrt{6}\] times faster

  • \[\sqrt{6}\] times slower

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Solution

(d)\[\sqrt{6}\] times slower

The acceleration due to gravity at moon is g/6.
Time period of pendulum is given by,

\[T = 2\pi\sqrt{\frac{l}{g}}\]

Therefore, on moon, time period will be :

Tmoon = \[2\pi\sqrt{\frac{l}{g_{moon}}} = 2\pi\sqrt{\frac{l}{( \frac{g}{6})}} = \sqrt{6}(2\pi\sqrt{\frac{l}{g}}) = \sqrt{6}T\]

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APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 12 Simple Harmonics Motion
MCQ | Q 18 | Page 251
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