# A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is - Physics

MCQ

A particle rotates in U.C.M. with tangential velocity V along a horizontal circle of diameter ‘D' . Total angular displacement of the particle in time 't' is..........

• vt

• (v/D)-t

• vt/2D

• 2vt/D

#### Solution

(2("vt"))/D

Velocity= v ; Diameter= D →Radius= D/2

omega=theta/t andv=r*omega

therefore v=D/2*theta/t

therefore theta=(2vt)/D

Concept: Uniform Circular Motion
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