Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11
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A Particle is Rotated in a Vertical Circle by Connecting It to a String of Length L And Keeping the Other End of the String Fixed. - Physics

MCQ

A particle is rotated in a vertical circle by connecting it to a string of length l and keeping the other end of the string fixed. The minimum speed of the particle when the string is horizontal for which the particle will complete the circle is

Options

  • \[\sqrt{gl}\]
     
  • \[\sqrt{2gl}\]
     
  • \[\sqrt{3gl}\]
     
  • \[\sqrt{5gl}\]
     
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Solution

\[\sqrt{3gl}\]
Suppose that one end of an extensible string is attached to a mass m, while the other end is fixed. The mass moves with a velocity v in a vertical circle of radius R. At some instant, the string makes an angle θ with the vertical as shown in the figure.

For a complete circle, the minimum velocity at L must be \[v_L = \sqrt{5gl}\] . 

Applying the law of conservation of energy, we have:
Total energy at M = total energy at L
\[\text{ i .e }  . , \frac{1}{2}m {v_M}^2 + mgl = \frac{1}{2}m {v_L}^2 \]
\[ \Rightarrow \frac{1}{2}m {v_M}^2 = \frac{1}{2}m {v_L}^2 - mgl\]
\[\text{ Using }  v_L \geq \sqrt{5gl}, \text{ we have} : \]
\[\frac{1}{2}m {v_M}^2 \geq \frac{1}{2}m(5gl) - mgl\]
\[ \therefore v_M = \sqrt{3gl}\]
 
  Is there an error in this question or solution?
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APPEARS IN

HC Verma Class 11, 12 Concepts of Physics 1
Chapter 8 Work and Energy
MCQ | Q 10 | Page 131
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