Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

# A Particle of Mass 1 G and Charge 2.5 × 10−4 C is Released from Rest in an Electric Field of 1.2 × 10 4 N C−1. How Long Will It Take for the Particle to Travel a Distance of 40 Cm? - Physics

Short Note

A particle of mass 1 g and charge 2.5 × 10−4 C is released from rest in an electric field of 1.2 × 10 4 N C−1.   How long will it take for the particle to travel a distance of 40 cm?

#### Solution

Given:
Charge of the particle, q = 2.5 × 10−4 C
Initial velocity, u = 0
Electric field intensity, E = 1.2 × 104 N/C
Mass of the particle, m = 1 g = 10−3 kg
Distance travelled, s = 40 cm = 4 × 10−1 m

Acceleration of the particle,

$a = \frac{F_e}{m} = \frac{3}{{10}^{- 3}} = 3 \times {10}^3 \text{ m/ s}^2$

Let t be the time taken by the particle to cover the distance s = 40 cm. Then,

$s = \frac{1}{2}a t^2$

$\Rightarrow t = \sqrt{\frac{2s}{a}} = 1 . 63 \times {10}^{- 2} s$

Concept: Electric Field - Electric Field Due to a System of Charges
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 7 Electric Field and Potential
Q 48.2 | Page 122