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A Particle of Mass 0.3 Kg is Subjected to a Force F = −Kx with K = 15 N/M. What Will Be Its Initial Acceleration If It is Released from a Point X = 20 Cm? - Physics

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Sum

A particle of mass 0.3 kg is subjected to a force F = −kx with k = 15 N/m. What will be its initial acceleration if it is released from a point x = 20 cm?

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Solution

Displacement of the particle from the mean position, x = 20 cm = 0.2 m
k = 15 N/m
Mass of the particle, m = 0.3 kg
Acceleration, \[a = \frac{\left| F \right|}{m}\]
\[\Rightarrow a = \frac{kx}{m} = \frac{15\left( 0 . 2 \right)}{0 . 3} = \frac{3}{0 . 3} = 10 m/ s^2\]
So, the initial acceleration when the particle is released from a point x = 20 cm is 10 m/s2.

Concept: Newton’s Second Law of Motion
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 5 Newton's Laws of Motion
Q 9 | Page 79
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