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# A Particle Executing Linear S.H.M. Has Velocities V1 and V2 at Distances X1 and X2 Respectively from the Mean Position. the Angular Velocity of the Particle is - Physics

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#### Question

A particle executing linear S.H.M. has velocities v1 and v2 at distances x1 and x2 respectively from the mean position. The angular velocity of the particle is _______

##### Options
• sqrt((x_1^2 - x_2^2)/(v_2^2 - v_1^2))

• sqrt((v_2^2 - v_1^2)/(x_1^2 - x_2^2))

• sqrt((x_1^2 + x_2^2)/(v_2^2 + v_1^2))

• sqrt((v_2^2 + v_1^2)/(x_2^2 + x_1^2))

#### Solution

sqrt((v_2^2 - v_1^2)/(x_1^2 - x_2^2))

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A Particle Executing Linear S.H.M. Has Velocities V1 and V2 at Distances X1 and X2 Respectively from the Mean Position. the Angular Velocity of the Particle is Concept: Differential Equation of Linear S.H.M..
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