Advertisement Remove all ads

# A Particle of Charge 2.0 × 10−8 C and Mass 2.0 × 10−10 G is Projected with a Speed of 2.0 × 103 M S−1 in - Physics

Sum

A particle of charge 2.0 × 10−8 C and mass 2.0 × 10−10 g is projected with a speed of 2.0 × 103 m s−1 in a region with a uniform magnetic field of 0.10 T. The velocity is perpendicular to the field. Find the radius of the circle formed by the particle and also the time period.

Advertisement Remove all ads

#### Solution

Given:
Charge of the particle, q = 2.0 × 10−8 C
Mass of the particle, m = 2.0 × 10−10 g
Projected speed of the particle, v = 2.0 × 103 m s−1
Uniform magnetic field, B = 0.10 T.
As per the question, the velocity is perpendicular to the field.
So, for the particle to move in a circle,the centrifugal force to the particle will be provided by the magnetic force acting on it.
Using qvB =(mv^2)/(r) , where r is the radius of the circle formed,
r = (mv)/(qB)
= (2xx10^-13xx2xx10^3)/(2xx10^-8xx0.10)
= 20 cm
Time period,
T = (2pim)/(qB)

= (2xx3.14xx2xx10^-13}/(2xx10^-8xx0.10)
= 6.28 × 10-4 s

Concept: Force on a Moving Charge in Uniform Magnetic and Electric Fields
Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 12 Magnetic Field
Q 30 | Page 232
Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?