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# A Parallel-plate Capacitor with Plate Area 20 Cm2 and Plate Separation 1.0 Mm is Connected to a Battery. the Resistance of the Circuit is 10 Kω. Find the Time Constant of the Circuit. - Physics

Sum

A parallel-plate capacitor with plate area 20 cm2 and plate separation 1.0 mm is connected to a battery. The resistance of the circuit is 10 kΩ. Find the time constant of the circuit.

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#### Solution

Given:-

Area of the plates, A = 20 cm2 = 20 × 10−4 m2

Separation between the plates, d = 1 mm = 1 × 10−3 m,

Resistance of the circuit, R = 10 kΩ

The capacitance of a parallel-plate capacitor,

$C = \frac{\in_0 A}{d}$

$= \frac{8 . 85 \times {10}^{- 12} \times 20 \times {10}^{- 4}}{1 \times {10}^{- 3}}$

$= \frac{8 . 85 \times {10}^{- 12} \times 2 \times {10}^{- 4}}{{10}^{- 3}}$

$= 17 . 7 \times {10}^{- 12} F$

Time constant = CR

= 17.7 × 10−12 × 10 × 103

= 17.7 × 10−8 s

= 0.177 × 10−6 s

= 0.18 μs

Concept: The Parallel Plate Capacitor
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#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 10 Electric Current in Conductors
Q 62 | Page 202
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