Advertisement Remove all ads

# A Parallel Plate Air Condenser Has a Capacity of 20µF. What Will Be a New Capacity If: 1) The Distance Between the Two Plates is Doubled? 2) A Marble Slab of Dielectric - Physics

Answer in Brief
Sum

A parallel plate air condenser has a capacity of 20µF. What will be a new capacity if:

1) the distance between the two plates is doubled?

2) a marble slab of dielectric constant 8 is introduced between the two plates?

Advertisement Remove all ads

#### Solution

Capacitance between the parallel plates of the capacitor, C = 20 pF

Initially, distance between the parallel plates was d and it was filled with air. Dielectric constant of air, k = 1

Capacitance C, is given by the formula,

C = (k∈_0A)/d

= (∈_0A)/d

C = (Ain_0)/d = 20muF

if d' -> 2d        :. C' -> C/2 = 10 muF

If k = 8 introduce

C"  = (Ain_0)/d xxk = 20 xx 8 = 160 muF

Concept: The Parallel Plate Capacitor
Is there an error in this question or solution?
Advertisement Remove all ads

#### APPEARS IN

Advertisement Remove all ads
Advertisement Remove all ads
Share
Notifications

View all notifications

Forgot password?