A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a - Physics

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A parallel beam of light of wavelength 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen. Find the width of the slit.

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Solution

Wavelength of light beam, λ = 500 nm = 500 × 10−9 m

Distance of the screen from the slit, D = 1 m

For first minima, n = 1

Distance between the slits = d

Distance of the first minimum from the centre of the screen can be obtained as:

x = 2.5 mm = 2.5 × 10−3 m

It is related to the order of minima as:

`"n"lambda = "x" "d"/"D"`

`"d" = ("n"lambda"D")/"x"`

= `(1 xx 500 xx 10^(-9) xx 1)/(2.5 xx10^(-3))`

= 2 × 10−4 m

= 0.2 mm

Therefore, the width of the slits is 0.2 mm.

Concept: Diffraction of Light - Seeing the Single Slit Diffraction Pattern
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Chapter 10: Wave Optics - Exercise [Page 385]

APPEARS IN

NCERT Physics Class 12
Chapter 10 Wave Optics
Exercise | Q 10.19 | Page 385
NCERT Physics Class 12
Chapter 10 Wave Optics
Exercise | Q 19 | Page 385

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