# A Pair of Adjacent Coils Has a Mutual Inductance of 1.5 H. If the Current in One Coil Changes from 0 to 20 A in 0.5 s, What is the Change of Flux Linkage with the Other Coil? - Physics

Numerical

A pair of adjacent coils has a mutual inductance of 1.5 H. If the current in one coil changes from 0 to 20 A in 0.5 s, what is the change of flux linkage with the other coil?

#### Solution

Mutual inductance of a pair of coils, µ = 1.5 H

Initial current, I1 = 0 A

Final current I2 = 20 A

Change in current, dI = I2 − I1 = 20 − 0 = 20 A

Time taken for the change, t = 0.5 s

Induced emf, "e" = ("d"phi)/"dt" ............(1)

Where "d"phi is the change in the flux linkage with the coil.

Emf is related with mutual inductance as:

"e" = mu "dI"/"dt" .......................(2)

Equating equations (1) and (2), we get

("d"phi)/("dt") = mu("dl")/"dt"

"d"phi = 1.5 × (20)

= 30 Wb

Hence, the change in the flux linkage is 30 Wb.

Concept: Inductance - Mutual Inductance
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#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 6 Electromagnetic Induction
Exercise | Q 6.9 | Page 230
NCERT Class 12 Physics Textbook
Chapter 6 Electromagnetic Induction
Exercise | Q 9 | Page 230

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