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Numerical
A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0 × 10−7 m2, and its resistance is measured to be 5.0 Ω. What is the resistivity of the material at the temperature of the experiment?
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Solution
Length of the wire, l = 15 m
Area of cross-section of the wire, a = 6.0 × 10−7 m2
Resistance of the material of the wire, R = 5.0 Ω
Resistivity of the material of the wire = ρ
Resistance is related to resistivity as
R = `ρ "l"/"A"`
ρ = `("RA")/"l"`
= `(5 xx 6 xx 10^-7)/15`
= 2 × 10−7 Ω m
Therefore, the resistivity of the material is 2 × 10−7 Ω m.
Concept: Resistivity of Various Materials
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