# A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0 × 10−7 m2, and its resistance is measured to be 5.0 Ω. - Physics

Numerical

A negligibly small current is passed through a wire of length 15 m and uniform cross-section 6.0 × 10−7 m2, and its resistance is measured to be 5.0 Ω. What is the resistivity of the material at the temperature of the experiment?

#### Solution

Length of the wire, l = 15 m

Area of cross-section of the wire, a = 6.0 × 10−7 m2

Resistance of the material of the wire, R = 5.0 Ω

Resistivity of the material of the wire = ρ

Resistance is related to resistivity as

R = ρ "l"/"A"

ρ = ("RA")/"l"

= (5 xx 6 xx 10^-7)/15

= 2 × 10−7 Ω m

Therefore, the resistivity of the material is 2 × 10−7 Ω m.

Concept: Resistivity of Various Materials
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Chapter 3: Current Electricity - Exercise [Page 127]

#### APPEARS IN

NCERT Physics Part 1 and 2 Class 12
Chapter 3 Current Electricity
Exercise | Q 3.6 | Page 127
NCERT Class 12 Physics Textbook
Chapter 3 Current Electricity
Exercise | Q 6 | Page 127

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