Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 11

A Monkey is Sitting on a Tree Limb. the Limb Exerts a Normal Force of 48 N and a Frictional Force of 20 N. Find the Magnitude of the Total Force Exerted by the Limb on the Monkey. - Physics

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Sum

A monkey is sitting on a tree limb. The limb exerts a normal force of 48 N and a frictional force of 20 N. Find the magnitude of the total force exerted by the limb on the monkey.

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Solution

Given: The limb of the tree exerts a normal force of 48 N and a frictional force of 20 N.

So, resultant magnitude of the force if given by

\[R = \sqrt{\left( {48}^2 + {20}^2 \right)}\]

\[ = \sqrt{2304 + 400}\]

\[ = \sqrt{2704} = 52 N\]

∴ The magnitude of the total force exerted by the limb on the monkey is 52 N.

Concept: Work Done by a Constant Force and a Variable Force
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APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 1
Chapter 4 The Forces
Exercise | Q 5 | Page 63
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