Question
A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. In the following table, find the parts of base that need to be added.
Parts of red pigment | 1 | 4 | 7 | 12 | 20 |
parts of base | 8 | ... | ... | ... | ... |
Solution
The given mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. For more parts of red pigments, the parts of the base will also be more. Therefore, the parts of red pigments and the parts of base are in direct proportion. The given information in the form of a table is as follows.
Parts of red pigment | 1 | 4 | 7 | 12 | 20 |
parts of base | 8 |
x_{1} |
x_{2} | x_{3} | x_{4} |
According to direct proportion,
`x_1/4 = 8/1 => x_1 = 4 xx 8 = 32`
`x_2/7 = 8/1 => x_2 = 7 xx 8 = 56`
`x_3/12 = 8/1 => x_3 = 8 xx 12 = 96`
`x_4/20=8/1 => x_4 = 8 xx 20= 160`
The table can be drawn as follows.
Parts of red pigment | 1 | 4 | 7 | 12 | 20 |
parts of base | 8 |
32 |
56 | 96 | 160 |
Is there an error in this question or solution?
Solution A Mixture of Paint is Prepared by Mixing 1 Part of Red Pigments with 8 Parts of Base. in the Following Table, Find the Parts of Base that Need to Be Added. Concept: Concept of Direct Proportion.