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A Mixture of Paint is Prepared by Mixing 1 Part of Red Pigments with 8 Parts of Base. in the Following Table, Find the Parts of Base that Need to Be Added. - CBSE Class 8 - Mathematics

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Question

A mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. In the following table, find the parts of base that need to be added.

Parts of red pigment 1 4 7 12 20
parts of base 8 ... ... ... ...

 

Solution

The given mixture of paint is prepared by mixing 1 part of red pigments with 8 parts of base. For more parts of red pigments, the parts of the base will also be more. Therefore, the parts of red pigments and the parts of base are in direct proportion. The given information in the form of a table is as follows.

Parts of red pigment 1 4 7 12 20
parts of base 8

x1

x2 x3 x4

According to direct proportion,

`x_1/4 = 8/1 => x_1 = 4 xx 8 = 32`

`x_2/7 = 8/1 => x_2 = 7 xx 8 = 56`

`x_3/12 = 8/1 => x_3 = 8 xx 12 = 96`

`x_4/20=8/1 => x_4 = 8 xx 20= 160`

The table can be drawn as follows.

Parts of red pigment 1 4 7 12 20
parts of base 8

32

56 96 160

 

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APPEARS IN

 NCERT Solution for Mathematics Textbook for Class 8 (2018 to Current)
Chapter 13: Direct and Inverse Proportions
Ex. 13.10 | Q: 2 | Page no. 208

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Solution A Mixture of Paint is Prepared by Mixing 1 Part of Red Pigments with 8 Parts of Base. in the Following Table, Find the Parts of Base that Need to Be Added. Concept: Concept of Direct Proportion.
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