MCQ

A mason constructs a wall of dimensions (270 cm × 300 cm × 350 cm) with bricks, each of size (22.5 cm × 11.25 cm × 8.75 cm) and it is assumed that `1/8` space is covered by the mortar. Number of bricks used to construct the wall is

#### Options

11000

11100

11200

11300

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#### Solution

11200

Volume of wall = 270 × 300 × 350 cm^{3}

`"18 th of the wall filled with bricks" = (7/8xx270xx300xx350) "cm"^3`

`"Volume of each brick" = (225/10xx1125/100xx875/100) "cm"^3`

`=((9xx225xx35)/32) "cm"^3`

Number of bricks used to construct the wall `= "Volume of the wall compared of bricks"/"Volume of each brick"`

`=(7xx270xx300xx350xx32)/(8xx9xx225xx35)`

`=11200`

Hence, the number of bricks used to construct the wall is 11200.

Concept: Volume of a Combination of Solids

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