A Man’S Age is Three Times that of His Son, and in Twelve Years He Will Be Twice as Old as His Son Would Be. What Are Their Present Ages. - Mathematics

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Sum

A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.

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Solution

Let present age of the son = x years

present age of the man = 3x years

In 12 years :

Son’s age will be = (x + 12) years

The man’s age will be = (3x + 12) years

According to the statement :

3x + 12 = 2(x + 12)

⇒ 3x + 12 = 2x + 24

⇒ 3x – 2x = 24 – 12

⇒ x = 12

3x = 3 x 12 = 36

Hence, present age of the man = 36 years
Present age of the son = 12 years.

Concept: Solving Linear Inequations
  Is there an error in this question or solution?
Chapter 14: Linear Equations in one Variable - Exercise 14 (B) [Page 169]

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Selina Concise Mathematics Class 8 ICSE
Chapter 14 Linear Equations in one Variable
Exercise 14 (B) | Q 13 | Page 169
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