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Sum
A man is 42 years old and his son is 12 years old. In how many years will the age of the son be half the age of the man at that time?
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Solution
Man’s age = 42 years
Son’s age = 12 years
Let after x years the age of the son will be half the age of the man.
Man’s age after x years = (42 + x) years
Son’s age after x years = (12 + x) years
According to the statement :
`12 + "x" = (42 + "x")/2`
⇒ 2(12 + x) = 42 + x ...(by cross multiplying)
⇒ 24 + 2x = 42 + x
⇒ 2x - x = 42 - 24
⇒ x = 18
Hence after 18 years, the age of the son will be half the age of the man
Concept: Solving Linear Inequations
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