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A Man Holds a Spherical Shaving Mirror of Radius of Curvature 60 Cm, and Focal Length 30 Cm, at a Distance of 15 Cm, from His Nose. Find the Position of Image, and Calculate the Magnification. - Science

A man holds a spherical shaving mirror of radius of curvature 60 cm, and focal length 30 cm, at a distance of 15 cm, from his nose. Find the position of image, and calculate the magnification. 

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Solution

Distance of the object, i.e. nose, from the mirror (u) = -15 cm
The focal length of the concave mirror (f) = -30 cm
We have to find the distance of the image (v).
Using the mirror formula, we get  
`1/f=1/v+1/u` 
`1/-30=1/v-1/15` 
`or 1/v=1/15-1/30` 
`or 1/v=(2-1)/30` 
`or 1/v=1/30` 
v=30 cm  
Thus, the position of the image is 30 cm behind the mirror.
Now, using the magnification formula, we get 
`m=(-v)/u` 
`m=(-30)/-15=2` 
Therefore, the image is 2 times magnified than the object.
  Is there an error in this question or solution?
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APPEARS IN

Lakhmir Singh Class 10 Physics (Science)
Chapter 4 Reflection of Light
Q 30 | Page 199
Lakhmir Singh Class 10 Physics (Science)
Chapter 4 Reflection of Light
Q 30 | Page 199
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