#### Question

A man bought an article for Rs x and sold it for Rs 16. If his loss was x per cent, find the cost price of the article.

#### Solution

C.P. of the article = Rs x

S.P. of the article = Rs 16

Loss = Rs (x – 16)

We know:

Loss% = `"Loss"/"CP" xx 100`

`:. x = (x - 16)/x xx 100`

`x^2 = 100x - 1600`

`x^2 - 100x + 1600 = 0`

(x - 80)(x - 20) = 0

x = 80, 20

Thus, the cost price of the article is Rs 20 or Rs 80.

Is there an error in this question or solution?

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A Man Bought an Article for Rs X and Sold It for Rs 16. If His Loss Was X per Cent, Find the Cost Price of the Article. Concept: Quadratic Equations.

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