A Man Bought a Certain Number of Oranges; Out of Which 13 Percent Were Found Rotten. He Gave 75% of the Remaining in Charity and Still Has 522 Oranges Left. Find How Many Had He Bought? - Mathematics

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Sum

A man bought a certain number of oranges; out of which 13 percent were found rotten. He gave 75% of the remaining in charity and still has 522 oranges left. Find how many had he bought?

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Solution

Suppose number of oranges bought = 100
Number of Rotten oranges
= `(13)/(100) xx 100`
= 13
Remaining oranges = 87
Oranges given in charity
= `(75)/(100) xx 87`

= `3 xx (87)/(4)`

= `(261)/(4)`

Net balance of oranges
= `87 - (261)/(4)`

= `(348 - 261)/(4)`

= `(87)/(4)`

If the balance is `(87)/(4)` then number of oranges bought = 100
If the balance is 1 then number of oranges bought = `100 xx (4)/(87)`
if the balance is 522 then number of oranges bought
= `100 xx (4)/(87)xx 522`

= `(100 xx 4 xx 522)/(87)`
= 100 x 4 x 6
= 2400

Concept: Concept of Percent and Percentage
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APPEARS IN

Selina Concise Mathematics Class 8 ICSE
Chapter 7 Percent and Percentage
Exercise 7 (B) | Q 1 | Page 85
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