Department of Pre-University Education, KarnatakaPUC Karnataka Science Class 12

# A Magnetic Needle is Free to Rotate in a Vertical Plane Which Makes an Angle of 60° with the Magnetic Meridian. If the Needle Stays in a Direction Making an Angle of Tan − 1 ( 2 √ 3 ) - Physics

Sum

A magnetic needle is free to rotate in a vertical plane which makes an angle of 60° with the magnetic meridian. If the needle stays in a direction making an angle of tan^-1(2sqrt(3)) with the horizontal, what would be the dip at that place?

#### Solution

Given :
Angle made by the magnetic meridian with the plane of rotation of the needle , θ = 60^circ

Angle made by the needle with the horizontal, δ_1 = tan^-1(2/sqrt(3))

If δ is the angle of dip , then

tan  δ_1 = tanδ/cosθ

⇒ tan  δ = tan  δ_1  cos θ

⇒ tan  δ = tan (tan^-1  2/sqrt3) cos60^circ

⇒ tan  δ = 2/sqrt(3) xx 1/2 = 1/sqrt(3)

⇒ δ = 30^circ

Is there an error in this question or solution?

#### APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 14 Permanent Magnets
Q 14 | Page 277