Advertisement Remove all ads

A Long, Straight Wire of Radius R Carries a Current Distributed Uniformly Over Its Cross Section. T He Magnitude of the Magnetic Field is - Physics

Short Note

A long, straight wire of radius R carries a current distributed uniformly over its cross section. T he magnitude of the magnetic field is
(a) maximum at the axis of the wire
(b) minimum at the axis of the wire
(c) maximum at the surface of the wire
(d) minimum at the surface of the wire.

Advertisement Remove all ads

Solution

(b) minimum at the axis of the wire
(c) maximum at the surface of the wire
A long, straight wire of radius R is carrying current i, which is uniformly distributed over its cross section. According to Ampere's law,  

\[\oint \vec{B} . d \vec{l} = \mu_o i_{\text{inside}} \]
\[\text{ At surface,} \]
\[B \times 2\pi R = \mu_o i\]
\[ \Rightarrow B_{\text{ surface}} = \frac{\mu_o i}{2\pi R}\]
\[\text{ Inside}, B \times 2\pi r = \mu_o i' \text{for r }< R \]

Here i, is the current enclosed by the amperian loop drawn inside the wire.
Binside will be proportional to the distance from the axis.
On the axis
B =0  
The magnetic fields from points on the cross section will point in opposite directions and will cancel each other at the centre.

\[\text{ Outside, B } \times 2\pi r = \mu_o i\]
\[ \Rightarrow B_{\text{ outside}} = \frac{\mu_o i}{2\pi r}, r > R\]

Therefore, the magnitude of the magnetic field is maximum at the surface of the wire and minimum at the axis of the wire 

  Is there an error in this question or solution?
Advertisement Remove all ads

APPEARS IN

HC Verma Class 11, Class 12 Concepts of Physics Vol. 2
Chapter 13 Magnetic Field due to a Current
MCQ | Q 4 | Page 249
Advertisement Remove all ads

Video TutorialsVIEW ALL [1]

Advertisement Remove all ads
Share
Notifications

View all notifications


      Forgot password?
View in app×