MCQ

A liquid is contained in a vertical tube of semicircular cross section. The contact angle is zero. The force of surface tension on the curved part and on the flat part are in ratio

#### Options

1:1

1:2

π:2

2:π

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#### Solution

Let the height of the liquid-filled column be *L.*

Let the radius be denoted by* R*.

\[\text{ Total perimeter of the curved part = semi - circumference of upper area }= \pi r \]

\[\text{ Total surface tension force } = \pi RS\]

\[\text{ Total perimeter of the flat part = 2R } \]

\[\text{ Total surface tension force = 2RS }\]

\[\text{ Ratio of curved surface force to flat surface force } = \frac{\pi RS}{2RS} = \frac{\pi}{2}\]

\[\]

Concept: Surface Tension

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