A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.
Let OA be the wall and AB be the ladder.
Therefore, by Pythagoras theorem,
AB2 = OA + BO
(10 m)2 = (8m)2 + OB2
100 m2 = 64 m2 + OB2
OB2 = 36 m2
OB = 6 m
Therefore the distance of the foot of the ladder from the base of the wall is 6 m
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