Advertisement Remove all ads

Advertisement Remove all ads

Advertisement Remove all ads

A kite is flying at a height of 75 in from the level ground, attached to a string inclined at 60°. to the horizontal. Find the length of the string, assuming that there is no slack in it.

[Take `sqrt(3)` =1.732 ]

Advertisement Remove all ads

#### Solution

Let OX be the horizontal ground and A be the position of the kite.

Also, let O be the position of the observer and OA be the thread.

Now, draw AB ⊥ OX.

We have:

∠BOA= 60°,OA= 75m and ∠OBA = 90°

Height of the kite from the ground = AB = 75 m

Length of the string OA = xm

In the right ΔOBA,we have:

`(AB)/(OA ) = sin 60° = sqrt(3)/2`

`⇒ 75/x = sqrt(3)/2`

`⇒ x = (75xx2)/sqrt(3) = 150/1.732 = 86.6m`

Hence, the length of the string is 86.6m

Concept: Heights and Distances

Is there an error in this question or solution?