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A Jet Plane is Travelling Towards West at a Speed of 1800 Km/H. What is the Voltage Difference Developed Between the Ends of the Wing Having a Span of 25 M - CBSE (Science) Class 12 - Physics

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Question

A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10−4 T and the dip angle is 30°.

Solution

Speed of the jet plane, v = 1800 km/h = 500 m/s

Wing spanof jet plane, l = 25 m

Earth’s magnetic field strength, B = 5.0 × 10−4 T

Angle of dip, `delta=30^@`

Vertical component of Earth’s magnetic field,

BV = B sin`delta`

= 5 × 10−4 sin 30°

= 2.5 × 10−4 T

Voltage difference between the ends of the wing can be calculated as:

e = (BV) × l × v

= 2.5 × 10−4 × 25 × 500

= 3.125 V

Hence, the voltage difference developed between the ends of the wings is

3.125 V.

  Is there an error in this question or solution?

APPEARS IN

 NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 6: Electromagnetic Induction
Q: 10 | Page no. 230
Solution A Jet Plane is Travelling Towards West at a Speed of 1800 Km/H. What is the Voltage Difference Developed Between the Ends of the Wing Having a Span of 25 M Concept: Faraday’s Law of Induction.
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