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# A Jet Plane is Travelling Towards West at a Speed of 1800 Km/H. What is the Voltage Difference Developed Between the Ends of the Wing Having a Span of 25 M - CBSE (Science) Class 12 - Physics

#### Question

A jet plane is travelling towards west at a speed of 1800 km/h. What is the voltage difference developed between the ends of the wing having a span of 25 m, if the Earth’s magnetic field at the location has a magnitude of 5 × 10−4 T and the dip angle is 30°.

#### Solution

Speed of the jet plane, v = 1800 km/h = 500 m/s

Wing spanof jet plane, l = 25 m

Earth’s magnetic field strength, B = 5.0 × 10−4 T

Angle of dip, delta=30^@

Vertical component of Earth’s magnetic field,

BV = B sindelta

= 5 × 10−4 sin 30°

= 2.5 × 10−4 T

Voltage difference between the ends of the wing can be calculated as:

e = (BV) × l × v

= 2.5 × 10−4 × 25 × 500

= 3.125 V

Hence, the voltage difference developed between the ends of the wings is

3.125 V.

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#### APPEARS IN

NCERT Solution for Physics Textbook for Class 12 (2018 to Current)
Chapter 6: Electromagnetic Induction
Q: 10 | Page no. 230

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Solution A Jet Plane is Travelling Towards West at a Speed of 1800 Km/H. What is the Voltage Difference Developed Between the Ends of the Wing Having a Span of 25 M Concept: Faraday’s Law of Induction.
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