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Sum
A hockey held is 91 metres 40 cm long and 55 metres wide. How long is the boundary of the held?
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Solution
The length of the field = 91 metres 40 cm = 9100 cm + 40 cm
= 9140 cm.
The width of the held = 55 metre = 55 × 100 = 5500 cm
Therefore boundary = length + width + length + width
= 9140 + 5500 + 9140 + 5500
= 29280 cm
= 29280 ÷ 100 = 292 metre 80 cm
Concept: Fields and Fences
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