# A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl. - Mathematics

Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

["Assume "pi=22/7]

Advertisement Remove all ads

#### Solution

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2πr2

=2xx22/7(5.25cm)^2=173.25cm^2

Therefore, the outer curved surface area of the bowl is 173.25 cm2.

Concept: Surface Area of a Sphere
Is there an error in this question or solution?
Chapter 13: Surface Area and Volumes - Exercise 13.4 [Page 225]

#### APPEARS IN

NCERT Class 9 Maths
Chapter 13 Surface Area and Volumes
Exercise 13.4 | Q 8 | Page 225

#### Video TutorialsVIEW ALL [1]

Share
Notifications

Forgot password?