Question

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

`["Assume "pi=22/7]`

 

Answer 1

Inner radius of hemispherical bowl = 5 cm

Thickness of the bowl = 0.25 cm

∴ Outer radius (r) of hemispherical bowl = (5 + 0.25) cm

= 5.25 cm

Outer CSA of hemispherical bowl = 2πr²

`=2xx22/7(5.25cm)^2=173.25cm^2`

Therefore, the outer curved surface area of the bowl is 173.25 cm².