A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2.
Inner radius (r) of hemispherical bowl =(10.5/2)cm = 5.25 cm
Surface area of hemispherical bowl = 2πr2
= 173.25 cm2
Cost of tin-plating 100 cm2 area = Rs. 16
Cost of tin-plating 173.25 cm2 area`= Rs.(16xx173.25)/100`
= Rs 27.72
Therefore, the cost of tin-plating the inner side of the hemispherical bowl is Rs. 27.72.
Concept: Surface Area of a Sphere
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