Short Note
A gun of mass 3 kg fires a bullet of mass 30 g. The bullet takes 0.003 s to move through the barrel of the gun and acquires a velocity of 100 m/s. Calculate :
(i) the velocity with which the gin recoils.
(ii) the force exerted on gunman due to recoil of the gun
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Solution
Mass of bullet, m = 30 g
= `30/1000` kg
= 0.03 kg
Velocity of bullet, v = 100 m/s
Mass of gun, M = 3 kg
Recoil velocity of gun , `V = -(0.03 xx 100)/3`
⇒ V = `-3/3`
⇒ V = -1 m/s
Concept: Conservation of Momentum
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