Sum
A fruit-seller sells 4 oranges for Rs. 3, gaining 50%. Find :
(i) C.P. of 4 oranges,
(ii) C.P. of one orange.
(iii) S.P. of one orange.
(iv) profit made by selling one orange.
(v) a number of oranges brought and sold in order to gain Rs. 24.
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Solution
S.P.of 4 oranges = Rs.3
∴ S.P. of 1 orange = Rs.`3/4`, Gain = 50%
S.P. =`("C.P."xx150)/100`
∴ C.P. of 1 orange = `(100xx"S.P.")/((100+50))`
`(100xx3/4)/150=75/150`
= Rs.`1/2`
(i) C.P. of 4 orange = `4xx1/2` = Rs.2
(ii) C.P. of 1 orange = Rs.`1/2` = Rs. (0.50)
(iii) S.P. of 1 orange = Rs. `3/4` = Rs.0.75
(iv) Profit made by selling one orange
`="Rs."3/4-"Rs."1/2="Rs."1/4="Rs."0.25`
(v) If gain is Rs. `1/4`, number of oranges = 1
If gain is Rs. 24, number of oranges =`1/(4/1)xx24`
`1xx4/1xx24=96`
Concept: To Find C.P., When S.P. and Gain (Or Loss) Percent Are Given
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