Question

A frequency distribution table for the production of oranges of some farm owners is given below. Find the mean production of oranges by 'assumed mean' method.

Production (Thousand rupees)	25 - 30	30 - 35	35 - 40	40 - 45	45 - 50
No. of Customers	20	25	15	10	10

Answer 1

Class (Production in Thousand rupees)	Class Mark xi	di = xi − A	Frequency (Number of farm owners) fi	Frequency × deviation fi × di
25 - 30	27.5	−10	20	−200
30 - 35	32.5	−5	25	−125
35- 40	37.5= A	0	15	0
40 - 45	42.5	5	10	50
45 - 50	47.5	10	10	100
			\[\sum f_i = 80_{}\]	\[\sum_{} f_i d_i = - 175\]

Required Mean = \[A + \frac{\sum_{} f_i d_i}{\sum_{} f_i}\]
\[37 . 5 - \frac{175}{80}\]
= 37.5 − 2.19
​= 35.31 thousand rupees
= Rs 35310
Hence, the mean production of oranges is Rs 35310.