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A Frequency Distribution Table for the Production of Oranges of Some Farm Owners is Given Below. Find the Mean Production of Oranges by 'Assumed Mean' Method. - Algebra

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Sum

A frequency distribution table for the production of oranges of some farm owners is given below. Find the mean production of oranges by 'assumed mean' method.

Production
(Thousand rupees)
25 - 30 30 - 35 35 - 40 40 - 45 45 - 50
No. of Customers 20 25 15 10 10
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Solution

Class
(Production in
Thousand rupees)
Class Mark
xi
di = x− A Frequency
(Number of farm owners)
fi
Frequency × deviation
f× d
25 - 30  27.5 −10 20 −200
30 - 35 32.5 −5 25 −125
35- 40 37.5= A 0 15 0
40 - 45 42.5 5 10 50
45 - 50 47.5 10 10 100
      \[\sum f_i = 80_{}\]
\[\sum_{} f_i d_i = - 175\]

Required Mean = \[A + \frac{\sum_{} f_i d_i}{\sum_{} f_i}\]
\[37 . 5 - \frac{175}{80}\]
= 37.5 − 2.19
​= 35.31 thousand rupees
= Rs 35310
Hence, the mean production of oranges is Rs 35310.

Concept: Tabulation of Data
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APPEARS IN

Balbharati Mathematics 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.1 | Q 4 | Page 138
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