A frequency distribution table for the production of oranges of some farm owners is given below. Find the mean production of oranges by 'assumed mean' method. Production (Thousand rupees) - Algebra

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A frequency distribution table for the production of oranges of some farm owners is given below. Find the mean production of oranges by 'assumed mean' method.

Production
(Thousand rupees)
25 - 30 30 - 35 35 - 40 40 - 45 45 - 50
No. of Customers 20 25 15 10 10
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Solution

Class
(Production in
Thousand rupees)
Class Mark
xi
di = x− A Frequency
(Number of farm owners)
fi
Frequency × deviation
f× d
25 - 30  27.5 −10 20 −200
30 - 35 32.5 −5 25 −125
35- 40 37.5= A 0 15 0
40 - 45 42.5 5 10 50
45 - 50 47.5 10 10 100
      \[\sum f_i = 80_{}\]
\[\sum_{} f_i d_i = - 175\]

Required Mean = `bard = (∑f_i d_i)/N`

= `(-35)/16`

= - 2.19

Mean `(barX)` = `A + bard`

= 37.5 - 2.19

= 35.31

= 35.31 × 1000

= Rs 35,310
Hence, the mean production of oranges is Rs 35,310.

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Chapter 6: Statistics - Practice Set 6.1 [Page 138]

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Balbharati Maths 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.1 | Q 4 | Page 138

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