# A Frequency Distribution of Funds Collected by 120 Workers in a Company for the Drought Affected People Are Given in the Following Table. Find the Mean of the Funds by 'Step Deviation' Method. - Algebra

Sum

A frequency distribution of funds collected by 120 workers in a company for the drought affected people are given in the following table. Find the mean of the funds by 'step deviation' method.

 Fund (Rupees) 0 - 500 500 - 1000 1000 - 1500 1500 - 2000 2000 - 2500 No. of workers 35 28 32 15 10

#### Solution

 Class (Production in Thousand rupees) Class Markxi di = xi − A $u_i = \frac{d_i}{h}$ Frequency(Number of farm owners)fi Frequency × deviationfi × ui 0 - 500 250 −1000 −2 35 −70 500 - 1000 750 −500 −1 28 −28 1000 - 1500 1250 = A 0 0 32 0 1500 - 2000 1750 500 1 15 15 2000 - 2500 2250 1000 2 10 20 $\sum f_i = 120_{}$ $\sum_{} f_i u_i = - 63$

Required Mean = $A + h\frac{\sum_{} f_i u_i}{\sum_{} f_i}$
$= 1250 - \left( \frac{63}{120} \right)500$
= 1250 − 262.5
​= Rs 987.5
Hence, the mean of the funds is Rs 987.5.

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Chapter 6: Statistics - Practice Set 6.1 [Page 138]

#### APPEARS IN

Balbharati Maths 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.1 | Q 5 | Page 138

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