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A Frequency Distribution of Funds Collected by 120 Workers in a Company for the Drought Affected People Are Given in the Following Table. Find the Mean of the Funds by 'Step Deviation' Method. - Algebra

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Sum

A frequency distribution of funds collected by 120 workers in a company for the drought affected people are given in the following table. Find the mean of the funds by 'step deviation' method.

Fund (Rupees)
0 - 500 500 - 1000 1000 - 1500 1500 - 2000 2000 - 2500
No. of workers 35 28 32 15 10
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Solution

Class
(Production in
Thousand rupees)
Class Mark
xi
di = x− A
\[u_i = \frac{d_i}{h}\]
Frequency
(Number of farm owners)
fi
Frequency × deviation
f× ui
0 - 500  250 −1000 −2 35 −70
500 - 1000  750 −500 −1 28 −28
1000 - 1500  1250 = A 0 0 32 0
1500 - 2000  1750 500 1 15 15
2000 - 2500  2250 1000 2 10 20
       
\[\sum f_i = 120_{}\]
\[\sum_{} f_i u_i = - 63\]

Required Mean = \[A + h\frac{\sum_{} f_i u_i}{\sum_{} f_i}\]
\[= 1250 - \left( \frac{63}{120} \right)500\]
= 1250 − 262.5
​= Rs 987.5
Hence, the mean of the funds is Rs 987.5.

Concept: Tabulation of Data
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APPEARS IN

Balbharati Mathematics 1 Algebra 10th Standard SSC Maharashtra State Board
Chapter 6 Statistics
Practice Set 6.1 | Q 5 | Page 138

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