Advertisement Remove all ads
Advertisement Remove all ads
Advertisement Remove all ads
A farmer borrows Rs.1,000 and agrees to repay with a total interest of Rs. 140 in 12 installments, each installment being less that the preceding installment by Rs. 10. What should be his first installment?
Advertisement Remove all ads
Solution
As each installment being less that the preceding installment by Rs. 10 the
installments are in A.P.
S12 = 1000 + 140 = 1140
n = 12, d = -10
`s_n=n/2[2a+(n-1)d]`
`s_12=12/2[2a+(11)(-10)]`
`1140=6[2a-110]`
`1140/6=[2a-110]`
190=[2a-110]
2a=190+110
2a=300
a=300/2
a=150
The first installment = Rs. 150.
Concept: Arithmetic Progression
Is there an error in this question or solution?