Sum

A fair die is thrown two times. Find the chance that the first throw gives an odd number and second throw gives multiple of 3.

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#### Solution

If a fair die is thrown twice, the sample space is

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

∴ n(S) = 36

Let event E: First throw gives an odd number (1, 3, or 5) and the second throw gives multiple of 3 (3 or 6).

E = {(1, 3), (1, 6), (3, 3), (3, 6), (5, 3), (5, 6)}

∴ n(E) = 6

∴ P(E) = `("n"("E"))/("n"("S"))`

= `6/36`

= `1/6`

Concept: Elementary Properties of Probability

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