A drop of solution (volume 0.05 ml) contains 3.0 × 10-6 mole of H+. If the rate constant of disappearance of H+ is 1.0 × 107 mole l-1s-1. It would take for H+ in drop to disappear in ______ × 10-9s. - Chemistry (JEE Main)

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A drop of solution (volume 0.05 ml) contains 3.0 × 10-6 mole of H+. If the rate constant of disappearance of H+ is 1.0 × 107 mole l-1s-1. It would take for H+ in drop to disappear in ______ × 10-9s.

Options

  • 6.00

  • 2.00

  • 9.00

  • 4.00

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Solution

A drop of solution (volume 0.05 ml) contains 3.0 × 10-6 mole of H+. If the rate constant of disappearance of H+ is 1.0 × 107 mole l-1s-1. It would take for H+ in drop to disappear in 6.00 × 10-9s.

Explanation:

Concentration of drop = `"Mole"/"volume in ml" xx 1000`

`= (3.0 xx 10^-6)/0.05 xx 1000`

= 0.06 mol L-1

Disappearance of 107 mol L–1 takes 1 s

Disappearance of 0.06 mol L–1 will take

`0.06/10^7 = 6.00 xx 10^-9`s

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