# A Drinking Glass is in the Shape of the Frustum of a Cone of Height 21 Cm with 6 Cm and 4 Cm as the Diameters of Its Two Circular Ends. Find the Capacity of the Glass. - Mathematics

Sum

A drinking glass is in the shape of the frustum of a cone of height 21 cm with 6 cm and 4 cm as the diameters of its two circular ends. Find the capacity of the glass.

#### Solution

Let R and r be the radii of the top and base, respectively, of the drinking glass and let its height be h.

Then, R =>  6/2 "cm" = 3  "cm", "r" => 4/2 "cm" = 2 "cm", h=21 "cm"

Capacity of the glass = Capacity of the frustum of the cone

=(pi"h")/3["R"^2+"r"^2+"Rr"]

=22/7xx1/3xx21xx[(3)^2+(2)^2+(3xx2)]"cm"^3

= (22 × 19) cm3

= 418 cm3

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#### APPEARS IN

RS Aggarwal Secondary School Class 10 Maths
Chapter 19 Volume and Surface Area of Solids
Formative Assessment | Q 9 | Page 937

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