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A DNA segment has a total of 1000 nucleotides, out of which 240 of them are adenine containing nucleotides. How many pyrimidine bases this DNA segment possesses? - Biology

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A DNA segment has a total of 1000 nucleotides, out of which 240 of them are adenine containing nucleotides. How many pyrimidine bases this DNA segment possesses?

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Solution

Cytosine and thymine are pyrimidines.

According to Chargaff's rule, ratio of purines to pyrimidines is equal.

Thus, the number of adenine (A) will be equal to the number of thymine (T).

Number of adenine (A) containing nucleotides = 240
Thus, A = T = 240

Therefore, A + T = 240 + 240 = 480

The number of cytosine (C) will be equal to the number of guanine (G).

Thus, G + C = Total number of nucleotides - Nucleotides containing A and T nitrogenous bases
                   = 1000 − 480
                   = 520

Therefore, G =260, C = 260

Number of guanine will be equal to number of cytosine, which will be 260.

Therefore, the number of pyrimidines that the segment possess = C + T
                                                                                               = 260 + 240
                                                                                               = 500

Concept: Structure of DNA and RNA
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