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A die is thrown, then find the probability of the following events:
A is an Event: getting an odd number on the top upper surface of the die.
B is an Event: getting a perfect square on the upper surface of the die.
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Solution
When a die is thrown, the sample space (S) is given by
S = {1, 2, 3, 4, 5, 6}
∴n(S) = 6
Let A be the event of getting an odd number on the upper surface of the die.
Then A = {1, 3, 5}
∴n(A) = 3
`thereforeP(A)=(n(A))/(n(s))`
`=3/6`
`=1/2`
Let B be the event of getting a perfect square on the upper surface of the die.
Then B = {1, 4}
∴n(B)=2
P(B)=`(n(B))/(n(S))`
=`2/6`
=`1/3`
Concept: Basic Ideas of Probability
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