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A die is thrown, then find the probability of the following events:

A is an Event: getting an odd number on the top upper surface of the die.

B is an Event: getting a perfect square on the upper surface of the die.

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#### Solution

When a die is thrown, the sample space (S) is given by

S = {1, 2, 3, 4, 5, 6}

∴n(S) = 6

Let A be the event of getting an odd number on the upper surface of the die.

Then A = {1, 3, 5}

∴n(A) = 3

`thereforeP(A)=(n(A))/(n(s))`

`=3/6`

`=1/2`

Let B be the event of getting a perfect square on the upper surface of the die.

Then B = {1, 4}

∴n(B)=2

P(B)=`(n(B))/(n(S))`

=`2/6`

=`1/3`

Concept: Basic Ideas of Probability

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