Short Note
A die is thrown once. Find the probability of getting a number other than 3.
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Solution
Let E be the event of getting a number other than 3.
Then, the favourable outcomes are 1, 2, 4, 5 and 6.
Number of favourable outcomes = 5
∴ Probability of getting a number other than 3 = P (E) = `"Number of favourable outcomes"/"Total number of possible outcomes" = 5/6`
Concept: Concept Or Properties of Probability
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