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Sum
A die is thrown, find the probability of getting:
a number greater than 4
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Solution
A die has six numbers: 1, 2, 3, 4, 5, 6
∴ Number of possible outcomes = 6
a number greater than 4
Numbers of favourable outcomes = greater than four i.e. two number 5 and 6
P(E) = `"Number of favourable outcomes"/"Number of all possible outcomes"`
= `2/6 = 1/3`
Concept: Basic Ideas of Probability
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