Maharashtra State BoardHSC Commerce 12th Board Exam
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A die is thrown 4 times. If ‘getting an odd number’ is a success, find the probability of at most 2 successes - Mathematics and Statistics

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Sum

A die is thrown 4 times. If ‘getting an odd number’ is a success, find the probability of at most 2 successes

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Solution

Let X denote the number of odd numbers.

P(getting and odd number) = p = `(3)/(6) = (1)/(2)`

∴ q = 1 – p = `1 - (1)/(2) = (1)/(2)`

Given, n = 4

∴ X ∼ B`(4, 1/2)`
The p.m.f. of X is given by

P(X = x) = `""^4"C"_x(1/2)^x(1/2)^(4 - x)`

= `""^4"C"_x(1/2)^4 , x` = 0, 1,...,4

P(at most 2 successes)
= P(X ≤ 2)

= P(X = 0 or X = 1 or X = 2)

= P(X = 0) + P(X = 1) + P(X = 2)

= `(11)/(16)`

Concept: Random Variables and Its Probability Distributions
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