Answer 1

The sample space of the given experiment is given by
S = {1, 2, 3, 4, 5, 6}
∴ n (S) = 6

Let C be the event of occurrence of a multiple of 2 or 3.
       Then C = {2, 3, 4, 6}
      i.e. n (C) = 4

\[\therefore P\left( C \right) = \frac{\text{ Number of outcomes favourable to C } }{\text{ Total number of possible outcomes} } = \frac{n\left( C \right)}{n\left( S \right)} = \frac{4}{6} = \frac{2}{3}\]