Answer 1

Given that radius of a cylindrical jar(r) = 6cm

Depth/height of cylindrical jar (h) = 2cm

Let no of balls be ‘n’

Volume of a cylinder = πr²h

V₁`=22/7xx(6)^2xx2cm^3`       ..........(1)

Radius of sphere 1.5cm

So volume of sphere`=4/3pir^3`

`V^2 = 4/3xx22/7(1.5)^3cm^3`    .........(2)

Volume of cylindrical jar is equal to sum of volume of n spheres

Equating (1) and (2)

`22/7xx(6)^2xx2=nxx4/3xx22/4(1.5)^3`

`n=(v_1)/(v_2)`⇒ `n=(22/7xx(6)^2xx2)/(4/3xx22/7(1.5)^3`

n = 16

∴ No of spherical balls (n) = 16